http://livedocs.adobe.com/flex/3/langref/flash/display/Graphics.html#beginGradientFill()
So, how do you make a horizontal rectangle, with a vertical linear gradient? Everything I've tried (i.e. rotating it 90 degrees) gives me a solid colour. Here is one failure example (270 degree rotation, then translated back the height).
s.graphics.beginGradientFill(GradientType.LINEAR,
[0x666666,0x666666],[0.9,0.1],[0,255],
new Matrix(0,-1,1,0,height,0));
s.graphics.drawRect(x,y,width,height);
(I'm actually giving up and will instead make this 9 pixel high gradient (a fancy drop shadow effect) by drawing 9 lines! But, please, somebody must have some sample code they can share?)
3 comments:
Hey Darren,
I think I've got a solution for you. All that you were missing is that third property inside of the matrix that specifies rotation by radians. I hope it's not so late that you've created that gradient line by line.
var shape1:Shape = new Shape();
var matrix:Matrix = new Matrix();
matrix.createGradientBox(163, 24, (Math.PI/180)*90, 0, 00);
var colors:Array = [ 0xffffff, 0x000000];
var alphas:Array = [ 1.0, 1.0];
var ratios:Array = [ 0, 255];
shape1.graphics.lineStyle(2,0xa1b0b6);
shape1.graphics.beginGradientFill(GradientType.LINEAR,colors, alphas, ratios, matrix);
shape1.graphics.drawRect( 0.0, 0.0, 163, 24);
shape1.graphics.endFill();
addChild(shape1);
Thanks to you, Darren and thanks to Piston Honda too for help me to resolve this problem!
Greetings.
Make sure you set your:
SpreadMethod.REPEAT;
And within your matrix set rotation to:
matrix.createGradientBox( 4000, 200, (Math.PI / 180) * 90 , 0, 0 );
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